Use awk to selectively zero left-pad certain fields only -

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my file has following format:

1/2/2559,11:58:00,4/1/2559,09:36:04,10,55,my name

i want use awk (among other things) left-pad 0 6th column.

for e.g., output may be:

my name,1/2/2559/11:58:00,10,0055,4/1/2559,09:35:04

so in example above, both 5th , 6th columns number fields want left pad 1 of fields.

the printf examples got other posts far (say using printf ($7,$1,$2,$5,"%04d\n",$6,$3,$4) seems scope in fields or terminates current row upon reaching field left-padded.

would appreciate pointers on this, thanks.

this doesn't match expected output posted don't see how input posted may you're looking for:

$ awk -f, '{printf "%s,%s,%s,%s,%04d,%s,%s\n",$7,$1,$2,$5,$6,$3,$4}' file name,1/2/2559,11:58:00,10,0055,4/1/2559,09:36:04

if not edit question explain mapping between sample input , expected output.

consider also:

$ awk 'begin{fs=ofs=","} {$6=sprintf("%04d",$6)} 1' file 1/2/2559,11:58:00,4/1/2559,09:36:04,10,0055,my name

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